Question

In the solution to the problem, why wouldn't you take half of the (t^2) value in the expression (1/2) a t^2 The question, and the solution to the problem are below. I was just confused why you would take half of the acceleration (3 m/s), but you wouldn't take half of the variable t^2

A car traveling at a constant speed of 24 m/s passes a trooper on the side of the road. One second after the car passes the trooper, the trooper then sets off in chase of the car at an acceleration of 3.00 m/s. a) How long does it take the trooper to overtake the car? b) How fast is the trooper going at that time? Use the equation s-so = vot + (1/2) (a) (t)^2

Solution:

24(t+1) = 0.5*3*t^2

24t +24 = 1.5 t^2 t^2

= 16t+16 t = 16.944s

b) stroopers speed = at = 16.944*3 = 50.832 m/s

Answer 1

for esv 七ト(17-94sec rp = 1-5 (17-94-1) 430m 17.9y 241/