Question

Find the angle between the given vectors. Round to the nearest tenth of a degree. u=6j, v= 71 – 7j O A. 52.7° OB. 135.0° O C.
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Answer #1

u=6i u=6 = 11-7; [v=y02 det product ū. - Uncos (6i). (ti-1i) = 6(7/2) loso - 42 = 42N2 coso To = 135.00 #re

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