Question

Score: U 2.5.95-LS A person x inches tall has a pulse rate of y beats per minute, as given approximately by - 1/3 y = 576x for 30 sxs 75. What is the instantaneous rate of change of pulse rate for the following heights ? (A) 33-inches ig (B) 70-inches What is the instantaneous rate of change of pulse rate for a 33 inch tall person? ady beats per minute per inch (Round to the nearest hundredth as needed.) -ad Text Chap Skills Tools Enter your answer in the answer box and then click Check Answer.

Answer 1

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Salmokrom wes. Given.lusie valk. y876zxs for 2042475 height ou: x AX 4x = y(x) = -574 로 -1.813911 Az ..dy min.be TD ax: -576170) 0.6685344 Al-0 AX r Now, the person in inchey . Y = f(x)= 5x² x= Height yam beats po minule .. f(1) 5*12= 5 .. Instantaneous Rate of change of pulse rate - all in +(1+0x) = 5(148x2 = 5(1+2.Ax+(6x)? > dy -Y-1,- 576 45 14). F(1+0x)-FO 5 (1+2.4x + (4x))-5 5 (1+2.4x+ 10x)-1) A) X3> 5. (2.4x + (x3 5 42 (2+ A2) en -576 (23;t*. -1926235" 2 E 1.811 beats per 5 (2+ 4) Am. 132 x=0 -192(701" vos leie f(1+0x)-fW. kin. S (2+4x) =5 (2+0) 3 AM 0 -0.67] Seat leone ses Learning function: 133 4.1 Y=f() = 63(1-1) y =305 ; 0<x59: ;*23, dx AX2 -0.125 Y = Numbs ofitears in xmo. am (63(1-x)) = 63 (0-692)504 Rate of Learning he stems to. oly = 504.dz. vers Af*=1; antes. Eſitemos bor. , At <=> Aty - 504,-0.125) Aus. 6). 42=9 og iteme /to = Et tawami zona flay = x3x+2 Ay y+ ay - y = f(2462) - f(x) = 631-407) - 6361-9) - Yt sy= f (z+4x) = (x + 4xy" – 3 (2+ 4xy +2 2631-24 02-1+$)= 65( 42402) z dy = (4x²6x).de 636 $4875) Now: Af x=2, 4x du: 0.2 168- 175.304 3478 ndys (4 (2) 6*2) -0.2 2 204D-2-4 -7.3042478 -7304 A. i). Ay (4+ 4y)- y = f(x+4x)=f(x) = f(240-2) - $(2) 24(2-2) - 3(2) = R.234-37127327 2-24+382-2 = 23.4256 - 14.52 - 16 +12 4.9056 dy dx A1 = -0.1: 2 +63(ons) 1750: dy -(4?=bx)