Question

Get Homework Help with Chege Stud. Student Home My Grades - 20-SP-CHEMIA Digital Resources for Chemist < Chapter 14/15 Homework 05/07/20 4.65 out of 24 This is a Numeric Entry question/It is worth 1 point/ You have unlimited attempts / There is a 5% att 04 Question (1 point) The value of the equilibrium constant K, for the formation of ammonia, N2(g) + 3H2(g) + 2NH,() is 4.50 x 10-S at 450°C. 1st attempt Ini See What is the value of K, for the following reaction? 2NH,($) - 3H,(s) + N2(g)

Answer 1

N₂(g) + 3H2(g) 2NH3(g) G = 4-50x10" 2 NH3 (9) = 3 +2) + 9,9) Kế • ! N2(g) + 3H2(g) 2 N3 (6) ke (why)? - [N,][H₂² 2NH3(g) + 3H2(g) +No . ]] Inverse this we ki's (his (2]" (N2 - [NH3]² can get can Got [Nf3]2 her ( 1745 - = 22222.22 ki = - Home 2. 2NH3(g) = 34 g) + No ca). Kop=22