Question

v=10.00 m/s v=0.00 m/s v=0.00 m/s x=20.00 m/s y of blue v of blue of yellow v of yellow run reset el=0.7 OD IDO

The 2000kg blue truck initially travels in the positive x-direction at 10m/s and the 1000kg yellow car initially travels in the positive y-direction at 20m/s. The elasticity of the collision is 0.7. The velocity of the truck in the x-direction is 8.69m/s and the velocity of the car in the x-direction is 2.62m/s. Assume that the friction force is negligible. Use momentum conservation principles to determine all of the final velocity components for the two vehicles. How much internal energy is produced during the collision?

(Answer to y-direction velocity components are 12.24m/s for the truck -4.49m/s for the car but please show how you got the y-direction velocities.)

Answer 1

C wonen Soth: Given data i) mi = 2000kg 11) Mz = 2000 kg 11) Uses = lowls 11) Uz2 = 0 mis iv) Uy, zomis v) Uy2 = 20mys And after collision: vi) V = 8.69 mis vii) x2 = 2.62 m/s Suppose after collision y-components are y, and Vyz here coefficient o restitution e = 07 Moio according to 'consequation of linear momentuma - net initial momentuou in X-clivection Pixo = fese and Pey = ffy hence m, Uxt + M₂ M = m, vt + M₂ Vaz | 2bOS Xte + Teve x2 = 22 BJX8.38 + poox2.2 Now momenure in y-direction muy & M₂ Ch = min + M2 Vyz Oy 2000 to +1000x20 = 2000x Vyl + 1000x Vyz or 2000km tlooo Vyz = 20000-0 from coefficiend of restitutibus ez Vyz - KHL OVH ku or yz - Vyl=elun Uyz) or by Vy = 0.7x(0-20) Eyl - Uy oy Vy - Vy - H4 S D now by solving equaciones we get Vy = 4.3 mys Vy2 = -2.67 wys Giren answer is incorrect: If you will use elasticity of collision 0.84 than a you will get given answer - Iedernek energy produced = loss in kinetic energy. - = Total initial K.E - Total final K E . =//mur + 1 M Uy) - [mive them wir + m2 van het m. 1 ] = (2000x10* +1000x20°) — [2000886997(1.317 +1000[2-62*+(+267)] = [600000-(4064/2.2 + 13993.3)] = 89797/ or Internel energy prockiced = 89.8 kg