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Consider 4 kg of tin-bismuth alloy (Sn-Bi) containing 20 wt% Bi at 180 °C. The phase diagram of the alloy is shown in the fig
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Answer #1

At 180c & 20 wts Bi 2 = lo wt% Bil ů = 33 wt / Bi W = = eo co-CB Ca-CB こ 20-10 33-10 10 - 0.4347 23 2 m = 4 X 0.434 7 = 1.74

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