dQ/dt = Cx dV/dt
dQ/dt = I (current) = 1.4 A
dV/dt = 1.5 x 10^6 V/s
C = 1.4/ 1.5 x 10^6
= 0.93 μF Answer
What capacitance, in mu F, has its potential difference increasing at 1.5 times 10^6 V/s when...
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