Solution:-
Given that,
mean =
= 15.0
standard deviation =
= 1.25
Using standard normal table,
P(Z < z) = 83%
= P(Z < z) = 0.83
= P(Z < 0.95) = 0.83
z = 0.95
Using z-score formula,
x = z *
+
x = 0.95 * 1.25 + 15.0
x = 16.19
Please determine the 83rd percentile of X. 32. Suppose the force acting on a column that...
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Answer both please or dont attempt.
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