Maximum emf E = 180 V
Angular speed w = 3300 rpm
= 3300 * 2(pi) rad / 60 s
= 345.57 rad / s
Area A= 1.9 * 10^-2 m ^ 2
Magnetic field B = 4.5 * 10 ^ -2 T
We know E = BANw
From this No.of truns N = E / ( BA w )
= 609.2 ~ 610
A generator is designed to produce a maximum emf of 180 Vwhile rotating with an angular...
A generator is designed to produce a maximum emf of 120 V while rotating with an angular speed of 3600 rpm. Each coil of the generator has an area of 0.033 m2. If the magnetic field used in the generator has a magnitude of 0.050 T, how many turns of wire are needed?
Homework Problem 23.46 A generator is designed to produce a maximum emf of 170 V while rotating with an angular speed of 3500 rpm Each coil of the generator has an area of 20x10-2 m2 Part A of the magnetic field used in the generator has a magnitude of 45x102T how many turns of wire are needed? Express your answer using two significant figures. ΨΗ ΑΣΦ και ? N: Submit Request Answer < Return to Assignment Provide Feedback
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