Part a).
Mass action reaction: Ar(g) + H2O(l) = Ar(aq)
Equilibrium expression: K = [Ar(aq)]/[Ar(g)]
Part b).
Gfo
= -RT ln(KH)
i.e. 8.36*1000 J/mol = -8.314 J/mol.K * (25+273.15) K * ln(KH)
i.e. ln(KH) = -3.3726
i.e. KH = e-3.3726 = 0.0343 or 3.43*10-2
Argon, a noble gas, partitions from the atmosphere into water. a) Write out the mass action...
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Physical Chemistry
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