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Chapter S4, Problem S4/018 The signboard truss is designed to support a horizontal wind load of 725 lb. A separate analysis s

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Answer #1

Sole force transmitted at point c (fe) = x125 453.125 lb Force transmitted at Point Band D FB fp = 3x725 = 135.94 lb - X 2Applying lamis theorum we get FD FDE sino sin(210) FED sin(90-0) 135.94 sin (28.61). FDE sin (270) fco Sin (90-28.64 on solvFree Baly Diagram of Point E FDE here 1 190-0) HE BC tunda FE СЕ FER 5.5 tanda 3 FIBE fo = 61.335€ Resolving the forces inEDE Co S{61:39)+ + F C G + For Cos(61.39) = F Sin (28.61) EF Put the value of FE and Fee we get – 283.89x6361.39)+(-453.125)+on Solving Equation (1) and (in we get FER = -473.146 lb And And FBE 189.252 ello to (Tensile nature]

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