Question

The graph of the function is shown. Find (or estimate) each of the items below. If the symbol oo oro applies, use it. If a limit does not exists and neither of these symbols applies, indicate the limit does not exists (DNE). If there is no answer, write "none." + + + + + + + (a) f(1) = (b) lim (3 - f(t)= (e) lim («f(x)]= (d) /'(2)= (e) lim ()= (1) f(x)dx = (8) Liv(n) – 1dx = (1) lim (L x + 6
A - H

Answer 1

b) solution Al to graph. Ô f(1) = ? solution :- at nil, then value of y = -3( In graph is denoted by dot) . Therefore value Ty = f(1) =-3 | Answer because N=1 c exact one) therefore we need to . answer the exact value of you f(1). and - the exact value is denoted by lot which is "37 Answer. b) lim 13 - f(x)) : 27-00 . Al to graph, when a tend's toward - oo the graph of f(n) is tending to ward "47 from both Left hand side and Right hand side, . There fore. Tim(3-flu) = lim (3) - lim f(u) -0% : 27-00 3) lim, als-fow) = 3-4 -- lim (3-$2)) = -1 ] Answer Mys0

(C) lim fu fon)] = ? (2) page. ->29 2 Now f(n) from graph. ? when a 1 +4E ........ then slople of line (m) f(a) f il 4 -0 -+ = +3-1 m = +2 .. x Ō + +2 +3 *☆ Note we had coloured hole because we want to - find the slope of line.. Then equation of line. ( y y -y, = m(n-u) €) Te :y-O = +2(x-1) y = 2x-le so If x=2 than y = 2x 2-1 3. y = 4-7 therefore f(2) = 3 Now approaching two » from left side. .. then we get f (2) com left side. 1 lim, Ge F(*)] = n (+2) (3) = 6 Answers +2

@ $112) = ? 3) page The geometrical meaning of f(n) mean slope of line of y = f(u) at u=2. In previous question "C? we had fine store equation of line. y= 22-1 f'(W) = 2 f'(n) = 2 ( constant for all value of us T there fore f'(2) = 2 Answar du (@) lim f(u) = ? 2-37 very - - Now approaching three from right side of graphfry » X --Got we get to . Fab therefore lim fw) = + 007 Answer 2-3t €) (flwch = ? The geomoriced meaning of liewy dhe in I . I ' . nel net area occupied by curve 1x23. f(u) from Therefore ifradra Arsa of Triangle = {x (-)x4, K21

у. (Чј рок - () [460-1 )du = ? Azou a y equation of line 1 from Jan Area = 8 fuldre.o how slope of above line from point (0,1) & (10) m=4 isy-O= -1(x-1) a y = -u+1 16x+1) I E tu {12. -(0-1) = ([ 0 +0 – (*+ 4)]- ()) = 1412-4) --) = -2 AM (50w-ijcke = -2 Amosur finns -2) = -2 Anos w lim [2² -f(w) - lim 1m² -f(n) 7 L2(n+1)%] 1900 [2C x2 +24+0) / Now when nem so thes f(u) o Therefore hom 214474) Site no
may be helpful for you...if you have any quires please discuss with me ,, I will help you...!!