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Shown to the right is a diagram of a boundry between two media, with a light...
4. a. A ray of light in water (n = 1.33) encounters an interface with a...
4. a. A ray of light in water (n = 1.33) encounters an interface with a piece of glass (n = 1.65). If the "grazing angle” (angle to the interface) is 30° in the water, calculate the angle of refraction of the ray in the glass. Sketch the ray in both media, correctly showing its "bend.” (Optional: Sketch the reflected ray, too.) 30° nwater = 1.33 n glass = 1.65 angle of refraction in glass: A. 37.4 B. 39.5° C....
3. (15 points) A light ray is traveling horizontally through air and hits the rectangular glass block shown to the right. The block has a triangular, air-filled cavity within it. You may take the...
3. (15 points) A light ray is traveling horizontally through air and hits the rectangular glass block shown to the right. The block has a triangular, air-filled cavity within it. You may take the index of refraction of air to be mair 1 and the index of refraction of glass to be nglass 1.5 40° く enters the glass block. Sketch this refracted ray on the diagram to the right. a. Calculate the angle of traction when the light ray...
3) Law of reflection (35 points) a. [10 points) On the diagram below, an incident ray...
3) Law of reflection (35 points) a. [10 points) On the diagram below, an incident ray is shown. Draw and label i. the normal ii. reflected ray iii. the angle of incidence and the angle of reflection b. [25 points) Below are five different combinations (a-e) of two mirrors (black lines) in each scenario with an incoming coming light ray shown (red or blue arrows). For each situation, complete the path that the incoming light ray will follow when bouncing...
To practice Tactics Box 18.1 Analyzing refraction. If a ray refracts between medium 1 and medium 2, having indices of...
To practice Tactics Box 18.1 Analyzing refraction. If a ray refracts between medium 1 and medium 2, having indices of refraction n1 and n2, the ray angles θ1 and θ2 in the two media are related by Snell's law, n1sinθ1=n2sinθ2. This law becomes a central idea in a procedure for analyzing refraction problems, as explained in the following Tactics Box. Draw a ray diagram. Represent the light beam with one ray. Draw a line normal to the boundary. Do this...
3. Optics problem set: a) [6 pts) An incident light ray in air strikes a glass...
3. Optics problem set: a) [6 pts) An incident light ray in air strikes a glass prism as shown. Sketch the ray diagram with the light rays refracted through each glass boundary. There is no total internal reflection in this problem. This ray diagram should include (1) normal lines, and (2) the qualitatively correct directions of refracted rays. b) [6 pts) Two converging lenses (#1 and #2) are given with an object as an arrow below. A pair of focal...
Snell's Law and the Law of Reflection explain how light is redirected when it encounters a...
Snell's Law and the Law of Reflection explain how light is redirected when it encounters a surface between two media. In the extreme, light may only reflect at a boundary, and go back into the medium it was in. More often, some of it reflects and some goes through. If the boundary is plane and flat, then these laws are easy to interpret. When the boundary is curved, they describe happens at every point on the surface. One of the...
In the figure, light is incident at angle theta_1 = 21.7 degree on a boundary between...
In the figure, light is incident at angle theta_1 = 21.7 degree on a boundary between two transparent materials. Some of the light then travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air. The index of refractions are n_1 = 1.22, n_2 = 1.40, n_3 = 1.32, n_4 = 1.52 and n_air = 1.00. What is the value of theta_4? What is the value of theta_5?
Partner: Date Name 11 Snell's Law Introduction When light passes from one material to another it ...
Partner: Date Name 11 Snell's Law Introduction When light passes from one material to another it is always bent away from its original path. This process is known as refraction and the change in direction depends on the change in optical density (or refractive index) of the two materials. A larger change in refractive index results in a larger change in angle between incoming and outgoing light beams. A light beam bends closer to the normal in the material with...
2.00 cm 5. In the diagram above a ray of light strikes a flat 2.00 cm-thick...
2.00 cm 5. In the diagram above a ray of light strikes a flat 2.00 cm-thick block of glass (n = 1.50) at an angle of 1 = 30.0° with the normal (shown as the dashed line). The angle of refraction at the upper surface is closest to d. 41.4° a. b. 70.5° 60.0° g. h. 12.2° 3.42° 30.0° 48.6° f. 19.5° 6. When the light ray passes through the glass block, it is shifted laterally by a distance d....
Answer the following. a. The ray of light shown passes from air (n_1 = 1) to...
Answer the following. a. The ray of light shown passes from air (n_1 = 1) to water (n_2 = 1.33) to glass (n_3 = 1.5). i. If the light enters the water at an angle of incidence of 40 degree, then what is the refracted angle in the glass? ii. How would the refracted angle in glass change if the water was removed? Explain. b. Green light (lambda = 546 nm) passes through a single slit. What width must the...
4. a. A ray of light in water (n = 1.33) encounters an interface with a piece of glass (n = 1.65). If the "grazing angle” (angle to the interface) is 30° in the water, calculate the angle of refraction of the ray in the glass. Sketch the ray in both media, correctly showing its "bend.” (Optional: Sketch the reflected ray, too.) 30° nwater = 1.33 n glass = 1.65 angle of refraction in glass: A. 37.4 B. 39.5° C....
3. (15 points) A light ray is traveling horizontally through air and hits the rectangular glass block shown to the right. The block has a triangular, air-filled cavity within it. You may take the index of refraction of air to be mair 1 and the index of refraction of glass to be nglass 1.5 40° く enters the glass block. Sketch this refracted ray on the diagram to the right. a. Calculate the angle of traction when the light ray...
3) Law of reflection (35 points) a. [10 points) On the diagram below, an incident ray is shown. Draw and label i. the normal ii. reflected ray iii. the angle of incidence and the angle of reflection b. [25 points) Below are five different combinations (a-e) of two mirrors (black lines) in each scenario with an incoming coming light ray shown (red or blue arrows). For each situation, complete the path that the incoming light ray will follow when bouncing...
3. Optics problem set: a) [6 pts) An incident light ray in air strikes a glass prism as shown. Sketch the ray diagram with the light rays refracted through each glass boundary. There is no total internal reflection in this problem. This ray diagram should include (1) normal lines, and (2) the qualitatively correct directions of refracted rays. b) [6 pts) Two converging lenses (#1 and #2) are given with an object as an arrow below. A pair of focal...
In the figure, light is incident at angle theta_1 = 21.7 degree on a boundary between two transparent materials. Some of the light then travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air. The index of refractions are n_1 = 1.22, n_2 = 1.40, n_3 = 1.32, n_4 = 1.52 and n_air = 1.00. What is the value of theta_4? What is the value of theta_5?
Partner: Date Name 11 Snell's Law Introduction When light passes from one material to another it is always bent away from its original path. This process is known as refraction and the change in direction depends on the change in optical density (or refractive index) of the two materials. A larger change in refractive index results in a larger change in angle between incoming and outgoing light beams. A light beam bends closer to the normal in the material with...
2.00 cm 5. In the diagram above a ray of light strikes a flat 2.00 cm-thick block of glass (n = 1.50) at an angle of 1 = 30.0° with the normal (shown as the dashed line). The angle of refraction at the upper surface is closest to d. 41.4° a. b. 70.5° 60.0° g. h. 12.2° 3.42° 30.0° 48.6° f. 19.5° 6. When the light ray passes through the glass block, it is shifted laterally by a distance d....
Answer the following. a. The ray of light shown passes from air (n_1 = 1) to water (n_2 = 1.33) to glass (n_3 = 1.5). i. If the light enters the water at an angle of incidence of 40 degree, then what is the refracted angle in the glass? ii. How would the refracted angle in glass change if the water was removed? Explain. b. Green light (lambda = 546 nm) passes through a single slit. What width must the...
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