Question

A single-phase full-bridge inverter as shown in Fig. 6.3(a) in the textbook has Vs = 98 V (DC), a load resistance of R-3 Ω, an output frequency off, = 2 kHz, and a modulation index of M = 0.9. It uses an uniform PWM as shown in Fig. 6.12(a) and has 5 pulses per half-cycle. Determine (a) the rms output voltage Vo, (b) the output (rms) power Po, (c) the average input current Is, (d) average current through each transistor lo, and (e) the rms current through each transistor IR I.

Answer 1

Given that a Single-phase full bridge inverter is circuit Here, the given values of an circuit is v_s = 98 v: R = 3 ohm: f_0 = 2 KHz: M = 0.9 (R = Resistance: f_0 = frequency: M = Modulation & v_s = source voltage). Doublerightarrow from the value of 1 to infinity phi full - bridge - inverter i) Here RMS output voltage v_0 is doublerightarrow v_0 rms = 0.9 v_s doublerightarrow 0.9 times 98 doublerightarrow 88.2 v therefore v_o rms = 88.2 v ii) Here the power output (P_0) is P_0 = V_o rms times I_o rms = 88.2 times 88.2/3 = 88.2 times 29.45 P_0 = 2597.49 w iii) Here the input current of an Average is I_avg = I_as doublerightarrow v_s/R = 98/3 = 33 A. iv) Here the current of Average through each transistor is I_Q = I_avg = 33/2 = 16.5 A V) Here Average current through each transistor I_Q is I_rms Q = 3.3 A.