Question

1. The Rh(I) complex below bears an inflexible ligand, occupying a square plane around the metal centre.

a) Draw the oxidative addition product of a generic species, X-Y to the complex. What is the new geometry around rhodium?

b) Would you expect H2 or MeI to oxidatively add to the Rh(I) complex?

c) What would these results imply about the mechanism of oxidative addition at this complex?

IN 心 “产 。

Answer 1

1 This is an inflexible to ligand, thus, it will try to be in square planer geometry. o Bra Rh men a) oxidative addition will result in adolition of x-y. Rb (1) Complex *- rendemes The new geometry For an is called octahedral Ly! geometry b) Yes, the the lonel mobecule will reaction with the complex to yield a Rh (ID) oxidative abolition production. The complex will go to a 18 e-specties from a 16e- species, c) It implies that the reaction goes through an intermediate, cohese find first & will add and give an intermediate, then y will attack it. Rh (1) Complex XY 3 Rh (D) x complex y Rh(111) compley