Question

6. Copper tubing is fed into an 1800°F furnace for annealing purposes. The conveyor must move at a constant 38.29 feet per minute. A 1755 RPM motor turns a 60:1 gearbox with a 6" output gear to drive the 10" conveyor gear. What size conveyor roller must be used to obtain the desired speed?

Answer 1

Schematic diagram of converyor belt drive System (conveyor roller) Conveyor Coupling Given that motor speed (ws) = 1755 RPM Gear box reducer ratio = 6001 - using is out put gear to drive the 10" conveyor gear ② condition - 60 - Wo W - 1785 w = 29-35 RPM toy * Condition © > Wq X 6 = .19 X 10" => W, = 63. x6 29-0545 Converyor speed(63) = 14-55 RPM Conveyor moves with 88.29 feet / minute = 80₂ V= Conveyor roller radius x W3 Con VE V = 38.29 = 12-1817 feet 1755 -9.1894 x 30.48 com radius = 66.5cm diameter of conveyor Roller = 133 CM +1-33 metics