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Using the table find the time in minutes for 90%
consolidation,t90 using the square root of...
Square-Root of Time (min) 15 10 1.00 inches) t90 = ? Dial Reading in 1/10,000 (Note...
Square-Root of Time (min) 15 10 1.00 inches) t90 = ? Dial Reading in 1/10,000 (Note 0 1150 Figure for Q24 announcement is closed for comments
2. A consolidation test was made on a sample of saturated clay in a circular ring with a height o...
2. A consolidation test was made on a sample of saturated clay in a circular ring with a height of 1.22 inches and an area of 4.91 square inches. Primary consolidation under the addition of each load was essentially complete at the end of 24 hours. The dial readings corresponding to the end of primary consolidation under each load increment are provided below. The initial void ratio was 1.70 Dial Reading (inch x 10 Pressure (tsf) 0.000 0.064 0.131 0.264...
9 The data shown in the table below were obtained from a laboratory consolidation test on...
9 The data shown in the table below were obtained from a laboratory consolidation test on a normally consolidated undisturbed MH soil with a liquid limit of 65. The sample was 62 mm in diameter, 25 mm tall and was tested under a double drainage condition Compute c, using the square root of time fitting method Time Since Loading (HH:MM:SS) 00:01:01 Dial Reading (mm) 7.21 7.74 00:03:06 00:08:35 00:16:39 8.40 9.01 9.60 00:30:15 00:59:17 10.11 01:54:29 10.35
Problem 3 In a laboratory consolidation test on a representative sample of cohesive soil, the original height of a d...
Problem 3 In a laboratory consolidation test on a representative sample of cohesive soil, the original height of a double-drained sample 50% consolidation was 5 min. The laboratory sample was taken from a soil layer which is 15 m thick in the field, doubly drained, and subjected to similar loading. How long will it take until the layer consolidates 50 %? b. If the final consolidation settlement is predicted to be 20 cm, how long will it take for a...
The results of a laboratory consolidation test on a clay specimen are given in the table...
The results of a laboratory consolidation test on a clay
specimen are given in the table
The initial height of the specimen is H=19 mm, specific gravity
is ?? = 2.68, moisture content is ? = 26%.
a. Draw the ? − log ?? ′ (?? ? − log ? ) curve (the student is
allowed to plot using spreadsheet)
b. Determine the preconsolidation stress
Question 1 (40 points): The results of a laboratory consolidation test on a clay specimen...
Could someone please help with this problem parts a-f 2. Use Figure 1 and Table 1...
Could someone
please help with this problem parts a-f
2. Use Figure 1 and Table 1 for the following a) Compute the vertical effective stress (o) in kN/m2 at the center of the clay layer prior to the construction of the footing. [Note: To compute c., you will first have to use the weight-volume relationships to compute the unit weight of the clay.] b) Assuming B 15 m, L 2.5 m, and Q-120 kN, use the Boussinesq procedure to determine...
The oedometer test data below was obtained from a sample of a clay soil when the...
The oedometer test data below was obtained from a sample of a clay soil when the loading increased from 200 to 400 kN/m² (Table Q8a). Table Q8a Time (min) Time (min) 0.00 0.25 1.00 2.25 4.00 Height (mm) 19.600 19.349 19.178 19.008 18.851 18,727 18.643 18.587 Height (mm) 18.555 18.515 18.505 18.497 18.490 18.483 18.477 18.449 6.25 9.00 12.25 100 400 (a) Using the 'square root of time method' determine the following: immediate compression (mm) primary consolidation (mm) coefficient of...
The time for 50% consolidation of a 25 mm thick clay specimen (drained at top and bottom) in the laboratory is 1...
The time for 50% consolidation of a 25 mm thick clay specimen (drained at top and bottom) in the laboratory is 150 sec. How long (in days) will it take for a 3 m thick layer of the same clay in the field under the same pressure increment to reach 75% consolidation? There is an impermeable shale layer at the bottom of the clay layer in the field I. 2. Use Figure 1 for the following Compute the vertical effective...
#6 table 2 8 LABORATORY REPORT 1C. TIME/DIV-S IC VOLTS/DIV-SV A VOLTS/DIV V ov o v...
#6
table 2
8 LABORATORY REPORT 1C. TIME/DIV-S IC VOLTS/DIV-SV A VOLTS/DIV V ov o v 0 s 2A. TIME/DIN-S2B. TIME/DIV 2C TIME/DIV-mS 2C. VOLTS/DIV o V 0 s 60033 0 s 3A. TIME/DIV-m 3A, VOLTS/DIV=-, 3B. TIME/DIV-1m 3B. VOLTS/DIV o v 0 s 0 s 388 Physics Laboratory Mamual Loyd A. TIME/DIV- ms 4A. VOLTS/DIV-LV o v ov 0 s 0 s 0 s Data Table 1 X Data Table 2 Voltmeter (V Voltmeter V 1.00 2.00 3.00 4.00...
lab question 1. What is the basis of the different purification methods? 2. What are some...
lab question 1. What is the basis of the different purification methods? 2. What are some of the factors the might have interfered with your results? 3. How might you improve the process to increase the yield and purity? lab process E. coli BL21 (DE3) cells were transformed with the pET Topo-1521 vector containing a reading frame encoding the green fluorescent protein (GFP). Cells were cultured in M9ZB media at 37°C until the absorbance at 600 nm reached 0.7, at...
Square-Root of Time (min) 15 10 1.00 inches) t90 = ? Dial Reading in 1/10,000 (Note 0 1150 Figure for Q24 announcement is closed for comments
2. A consolidation test was made on a sample of saturated clay in a circular ring with a height of 1.22 inches and an area of 4.91 square inches. Primary consolidation under the addition of each load was essentially complete at the end of 24 hours. The dial readings corresponding to the end of primary consolidation under each load increment are provided below. The initial void ratio was 1.70 Dial Reading (inch x 10 Pressure (tsf) 0.000 0.064 0.131 0.264...
9 The data shown in the table below were obtained from a laboratory consolidation test on a normally consolidated undisturbed MH soil with a liquid limit of 65. The sample was 62 mm in diameter, 25 mm tall and was tested under a double drainage condition Compute c, using the square root of time fitting method Time Since Loading (HH:MM:SS) 00:01:01 Dial Reading (mm) 7.21 7.74 00:03:06 00:08:35 00:16:39 8.40 9.01 9.60 00:30:15 00:59:17 10.11 01:54:29 10.35
Problem 3 In a laboratory consolidation test on a representative sample of cohesive soil, the original height of a double-drained sample 50% consolidation was 5 min. The laboratory sample was taken from a soil layer which is 15 m thick in the field, doubly drained, and subjected to similar loading. How long will it take until the layer consolidates 50 %? b. If the final consolidation settlement is predicted to be 20 cm, how long will it take for a...
The results of a laboratory consolidation test on a clay
specimen are given in the table
The initial height of the specimen is H=19 mm, specific gravity
is ?? = 2.68, moisture content is ? = 26%.
a. Draw the ? − log ?? ′ (?? ? − log ? ) curve (the student is
allowed to plot using spreadsheet)
b. Determine the preconsolidation stress
Question 1 (40 points): The results of a laboratory consolidation test on a clay specimen...
Could someone
please help with this problem parts a-f
2. Use Figure 1 and Table 1 for the following a) Compute the vertical effective stress (o) in kN/m2 at the center of the clay layer prior to the construction of the footing. [Note: To compute c., you will first have to use the weight-volume relationships to compute the unit weight of the clay.] b) Assuming B 15 m, L 2.5 m, and Q-120 kN, use the Boussinesq procedure to determine...
The oedometer test data below was obtained from a sample of a clay soil when the loading increased from 200 to 400 kN/m² (Table Q8a). Table Q8a Time (min) Time (min) 0.00 0.25 1.00 2.25 4.00 Height (mm) 19.600 19.349 19.178 19.008 18.851 18,727 18.643 18.587 Height (mm) 18.555 18.515 18.505 18.497 18.490 18.483 18.477 18.449 6.25 9.00 12.25 100 400 (a) Using the 'square root of time method' determine the following: immediate compression (mm) primary consolidation (mm) coefficient of...
The time for 50% consolidation of a 25 mm thick clay specimen (drained at top and bottom) in the laboratory is 150 sec. How long (in days) will it take for a 3 m thick layer of the same clay in the field under the same pressure increment to reach 75% consolidation? There is an impermeable shale layer at the bottom of the clay layer in the field I. 2. Use Figure 1 for the following Compute the vertical effective...
#6
table 2
8 LABORATORY REPORT 1C. TIME/DIV-S IC VOLTS/DIV-SV A VOLTS/DIV V ov o v 0 s 2A. TIME/DIN-S2B. TIME/DIV 2C TIME/DIV-mS 2C. VOLTS/DIV o V 0 s 60033 0 s 3A. TIME/DIV-m 3A, VOLTS/DIV=-, 3B. TIME/DIV-1m 3B. VOLTS/DIV o v 0 s 0 s 388 Physics Laboratory Mamual Loyd A. TIME/DIV- ms 4A. VOLTS/DIV-LV o v ov 0 s 0 s 0 s Data Table 1 X Data Table 2 Voltmeter (V Voltmeter V 1.00 2.00 3.00 4.00...
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