A proton of mass 1.67*10^-27 kg is accelerated by a field of 600 N/C. How fast...
A proton of mass 1.67*10^-27 kg is accelerated by a field of 600 N/C. How fast in m/s is it travelling after 20 nanoseconds if it has a charge of 1.60*10^-19 C?
Homework Answers
electric force on proton, F = q*E
m*a = q*E
a = q*E/m
= 1.6*10^-19*600/(1.67*10^-27)
= 5.75*10^10 m/s^2
Apply, v = u + a*t
= 0 + 5.75*10^10*20*10^-9
= 1.15*10^3 m/s
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A proton of mass 1.67*10^-27 kg is accelerated by a field of 600
N/C. How fast...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and a charge of q_p = 1.60 \times 10^{-19} ~Cq p =1.60×10 −19 C is moving through vacuum at a constant velocity of 10,000 ~m/s10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of | \vec{E} | = ∣ E ⃗ ∣=2.60e+3~N/C N/C . The region of uniform...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and a charge of q_p = 1.60 \times 10^{-19} ~Cq p =1.60×10 −19 C is moving through vacuum at a constant velocity of 10,000 ~m/s10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of | \vec{E} | = ∣ E ⃗ ∣=2.35e+3~N/C N/C . The region of uniform...
A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve? A proton of mass...
A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve?
A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve?
particle electron: proton: charge mass me = 9.11 × 10-31 kg me = 1.67 × 10-27...
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A proton of mass mp= 1.67×10−27 kg and a charge of qp= 1.60×10−19 C is moving...
A proton of mass mp= 1.67×10−27 kg and a charge of qp= 1.60×10−19 C is moving through vacuum at a constant velocity of 10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of E =3.62e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. How far (in meters) will the proton have been deflected towards the south by the...
PLS ANSWER THIS ASAP I WILL RATE proton (mass 1.67*10^ ^ -27 , charge ^-19 C)...
PLS ANSWER THIS ASAP I WILL RATE proton (mass 1.67*10^ ^ -27 ,
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A proton (mass = 1.67 x 10-27 kg, charge = 1.6 x 10-19 C) released from...
A proton (mass = 1.67 x 10-27 kg, charge = 1.6 x 10-19 C) released from rest inside a uniform electric field undergoes a displacement of 0.30 meters. The electric field has a magnitude 8.0x104 V/m, along the positive x-axis. a) What is the potential difference experienced by the proton? b) What is the the change in the electric potential energy of the proton due to this displacement? (pay attention to the sign). c) What is the spoed v of...
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If a proton m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is released from rest at the + plate in the below electric field, what will be its speed at the-plate? 3 cm E = 5000 N/C
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A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve?
A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve?
particle electron: proton: charge mass me = 9.11 × 10-31 kg me = 1.67 × 10-27 kg m, = 1.67 × 10-27 kg 9e =-1.60 × 10-19 C = +1.60 × 10-19 C neutron: Coulomb's law: F = kelellel/r2 where ke = 8.9875 × 10" N m?/C". Electric field: E = F/go- Electric field of a point charge: E kell/r2. 1. Sketch the electric field of a pair of oppositely charged particles.
PLS ANSWER THIS ASAP I WILL RATE proton (mass 1.67*10^ ^ -27 ,
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A proton (mass 1.67x10^-27 kg, charge 1.602x10^-19 C) is placed in a uniform electric field. The proton undergoes an acceleration of 10^11 m/s^2. a) What is the magnitude of the electric field? b) If the electric field is produced by two large parallel plates connected...
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If a proton m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is released from rest at the + plate in the below electric field, what will be its speed at the-plate? 3 cm E = 5000 N/C
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