A molecule of DNA (deoxyribonucleic acid) is 2.07 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.02% upon becoming charged. Determine the effective spring constant of the molecule.
Say, the force stays constant during compression.
The ends of the molecules become singly ionized meaning the
charge on both ends is "e".
[e = 1.6x10^-19 C ]
F = kQ²/r²
F =
(8.99x109)(1.6x10-19)²/(2.07x10-6)²
F = 5.371 x 10-17 N
F = Kx
x = 0.0102(2.07x10^-6)
5.371 x 10-17 = K(0.0102(2.07x10^-6) )
K = 2.543 x 10 -9N/m
A molecule of DNA (deoxyribonucleic acid) is 2.07 μm long. The ends of the molecule become...
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