Here, the protons will have the maximum velocity, when they have
the maximum attainable kinetic energy i.e. when
all the potential energy has converted to
kinetic energy.
Therefore
Uinitial = KEfinal
Uinitial=Electrostatic potential energy = kq1q2/r
Final kinetic energy of both the protons = 1/2(mv2)+ 1/2(mv2)
=> Uinitial = (9 x 109)(1.6 x 10-19)2/(1 x 10-9) = 23.04 x 10-20
=>mv2= 23.04 x 10-38
=> v = (23.04 x 10-20)/(1.67x10-27) = 1.1745 x 104 m/s
option A is correct
E) 6.6 x 10 Q4. Two protons are released from rest when they are 1.00 nm...
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