Solution :
Using standard normla table,
a ) P(Z < 1.29 )
P(Z < 1.29 ) = 0.9015
b ) P(Z < 2.8 )
P(Z < 2.8 ) = 0.9974
c ) P(Z > 1.45 )
= 1 - P(Z < 1.45 )
= 1 - 0.9265
= 0.0735
P(Z > 1.45 ) = 0.0735
d ) P(Z > - 2.15 )
= 1 - P(Z < - 2.15 )
= 1 - 0.0158
= 0.9842
P(Z > - 2.15 ) = 0.9842
e ) P(- 2.34 < Z < 1.76 )
= P(Z < 1.76 ) - P ( Z < -2.34 )
= 0.9608 - 0.0096
= 0.9512
P(- 2.34 < Z < 1.76 ) = 0.9512
Question 5 Use Appendix Table Ш to determine to 5 decimal places the following probabilities for...
Find the following probabilities for the standard normal random variable Z: (Give answers to four decimal places.) a) P(Z ≤ 2.1) b) P(Z ≥ 2.1) c) P(Z ≥ -1.65) d) P(-2.13 ≤ Z ≤ -.41) e) P(-1.45≤ Z ≤ 2.15) f) P(Z ≤ -1.43)
1. Use Appendix Table III to determine the following probabilities for the standard normal variable Z. a) P(-0.7<Z< 0.7) b) P(-1.5<Z<1.5) c) P(-2.0<Z<2.0) d) P(Z>2.0)=
HW 5-Due date: November 13, 2019 For each problem only answer those parts that are listed below not all parts. 4.63: (e) 4.65: (c) 4.71: (c) 4.83: (a) 4.119: (b) 4-63. Use Appendix Table III to determine the following probabilities for the standard normal random variable Z (a) P(Z<1.32) (c) P(Z>1.45) (e) P-2.34<Z<1.76) (b) P(Z<3.0) (d) P(Z>-2.15) 4-65. Assume that Z has a standard normal distribution. Use Appendix Table III to determine the value for z that solves each of...
Use the Standard Normal table to find the following probabilities. (Keep probabilities at 4 decimal places.) P(-1.49< z < 2.04) =
You may need to use the appropriate appendix table or technology to answer this question. Given that z is a standard normal random variable, compute the following probabilities. (Round your answers to four decimal places.) (a) P(z ≤ −1.0) (b) P(z ≥ −1) (c) P(z ≥ −1.7) (d) P(−2.7 ≤ z) (e) P(−3 < z ≤ 0)
Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). Use Table 1 in Appendix B. P(-1.93 z 0.49) P(0.59 z 1.26) P(-1.76 z -1.09)
You may need to use the appropriate appendix table to answer this question. Given that z is a standard normal random variable, compute the following probabilities. (Round your answers to four decimal places.) (a) P(-1.98 SZS 0.47) (b) P(0.54 sz s 1.24) (C) P(-1.75 SZS -1.02)
Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). Use Table 1 in Appendix B. a. P(-1.94 S z 3 0.43) b. PO.55 Sz 1.22) с. Р(-1.76 -1.02)
Find the value 2* that satisfies each of the following probabilities for a standard normal random variable Z. (Round your answers to two decimal places.) (a) P(Z sz*) - 0.0485 (b) PIZ sz*) = 0.9515 (c) P(-x* SZ SZ") - 0.903
given that z is a standard normal variable, compute the
following probabilities
You may need to use the appropriate appendix table or technology to answer this question. Given that z is a standard normal random variable, compute the following probabilities. (Round your answers to four decimal places.) (a) P(Z S -1.0) (b) P(Z > -1) (c) P(Z 2 -1.4) (d) PC-2.6 52) (e) P(-3 CZSO)