You have two containers of the same liquid. The first container has 98.0 g at T1

Question

Question

You have two containers of the same liquid. The first container has 98.0 g at T₁

Answer 1

Answer #1

apply the principle of calorimetry as

heat lost container 1 = heat lost by container 2

so m1c1 DT = m2 c2 DT

change of temperature of Contaner 1 is (T-42.6)

change of temperature of container 2 = ( 42.6-21) = 21.6 deg C

so as here sp heat c1 = c2

0.098 * (T1- 42.6) = 0.025 *(21.6)

T1-42.6 = 55.102

T1 = 55.102 + 42.6

T1 = 97.7 deg C --<<<<<<<<<<<<<<<<Answer

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Answer 2

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