Calculate Delta G for the following reaction:
Glutamate + NH3 glutamine + H2O
Where the reaction occurs at 293 kelvin, the change in heat is 19,070 calories, and the change in entropy is 90 cal/k.
Is this reaction endergonic or exergonic?
Calculate Delta G for the following reaction: Glutamate + NH3 glutamine + H2O Where the reaction...
To calculate the free energy (delta G^0,) of a reaction, you can subtract the free energies of formation (G_f^0) of the reactants from those of the products. Given the following data, what will be true of this reaction? C_6H_12O_6 + O_2 rightarrow CO_2 + H_2O G_f^0: -917.30 -394.4 -237.2 The reaction will not require a catalyst to proceed. The reaction is not balanced, so you cannot calculate the change in free energy. The reaction will be endergonic. The reaction will...
Biochemistry: 90. The heat enthalpy change in a reaction where delta G is -9.92 kJ/mol and delta S is -85.5 J/K at 25*C is: a. 35.39 kJ/mol b. -35.39 kJ/mol c. 25.48 kJ/mol d. -25.48 kJ/mol
Question 5 The spontaneity of a reaction depends both on the enthalpy change, Delta H, and entropy change, Delta S. Reactions that release energy produce more stable products, and the universe tends toward disorder. Thus, an exothermic reaction with a positive entropy change will always be spontaneous. Mathematically, this relationship can be represented as where Delta G is the change in Gibbs free energy and T is the Kelvin temperature. If Delta G is negative, then the reaction is spontaneous....
Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change in enthalpy (ΔH) for this reaction, using Hess' law and the enthalpy changes for the reactions given below. (1a) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l); ΔH = −1166.0 kJ/mol (2a) 2 NO(g) + O2(g) → 2 NO2(g); ΔH = −116.2 kJ/mol (3a) 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g); ΔH = −137.3 kJ/mol
Consider the reaction HCl(g)NH3(g)>NH4C1(s) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.45 moles of HCl(g) react at standard conditions. ASO surroundings J/K Consider the reaction HCl(g)NH3(g)>NH4C1(s) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.45 moles of HCl(g) react at standard conditions. ASO surroundings J/K
Consider the reaction 2CO(g) + 2NO(g) rightarrow 2CO_2(g) + N_2(g) for which Delta H degree = -746.6 kJ and Delta S degree = -198.0 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.514 moles of CO(g) react under standard conditions at 298.15 K. (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If...
Consider the reaction CO2(g) + H2(g)CO(g) + H2O(g) where S° rxn = 42.1 J/K Using standard thermodynamic data (in the Chemistry References), calculate the entropy change of the surroundings and the universe at 25°C. Ssurroundings = _____J K-1 mol-1 Suniverse = _____J K-1 mol-1
Part G Calculate AH for the following reaction: CH3OH(1) +O2(g) + HCOH(1) +H2O(1) Express the enthalpy in kilojoules to one decimal place. AC O O ? AH = Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part 1 Calculate AS for the following reaction: CHOH(1) +O2(g) + HCO-H1) +H2O(1) Express the entropy in joules per kelvin to one decimal place. IVO AED ROO? J/K AS = Submit Request Answer Part 1 From the values of AH°...
8.) From the values of delta H and delta S, calculate delta G then predict whether the following reactions would be spontaneous or not at 25 C. a) Reaction A: delta H= 10.5 kJ/mol, and delta S = 30 J/K mol b) Reaction B: delta H=1.8 kJ/mol, and delta S = -113 J/K mol 9.) Calculate the delta G and K, for the following equilibrium reaction at 25 C: 2H2O(Ⓡ) <-> 2H2(g) + O2(8) delta Gran H2O(x) = -228.6 kJ/mol
Self-test 4.7 (a) Calculate the standard reaction entropy for N2(g) + 3 H2(g)2 NH3 (g) at 25 °C. (b) What is the change in entropy when 2 mol H2 reacts? Answer: (a) (Using values from Table 4.2)-198.7 J K-1 mol-1; (b) -132.5 J K-1