1.) Voting records show that 61% of eligible voters actually did vote in a recent presidential election. In a survey of 1002 people, 70% said that they voted in that election.
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1.) Voting records show that 61% of eligible voters actually did vote in a recent presidential...
1107 people, 816 people said they voted in a recent presidential election. Voting records show that 71% of eligible voters actually did vote. Given that 71% of eligible voters actually did vote, (a) find the probability that among 1107 randomly selected voters, at least 816 actually did vote. (b) What do the results from part (a) suggest? (a) P(X ≥816) ? round 4 decimals
In a survey of 1425 people, 1045 people said they voted in a recent presidential election. Voting records show that 71% of eligible voters actually did vote. Given that 71% of eligible voters actually did vote, (a) find the probability that among 1425 randomly selected voters, at least 1045 actually did vote. (b) What do the results from part (a) suggest?
In a survey of 13181318 people, 877877 people said they voted in a recent presidential election. Voting records show that 6464% of eligible voters actually did vote. Given that 6464% of eligible voters actually did vote, (a) find the probability that among 13181318 randomly selected voters, at least 877877 actually did vote. (b) What do the results from part (a) suggest?
In a survey of 1145 people, 862 people said they voted in a recent presidential election. Voting records show that 73% of eligible voters actually did vote. Given that 73% of eligible voters actually did vote, (a) find the probability that among 1145 randomly selected voters, at least 862 actually did vote. (b) What do the results from part (a) suggest? (a) P(X>862)=
In a survey of 1127 people, 739 people said they voted in a recent presidential election. Voting records show that 63% of eligible voters actually did vote. Given that 63% of eligible voters actually did vote, (a) find the probability that among 1127 randomly selected voters, at least 739 actually did vote. (b) What do the results from part (a) suggest? (a) P(x≥739) = b) What does the result from part (a) suggest? A.People are being honest because the probability...
In a survey of 1466 people, 1049 people said they voted in a recent presidential election. Voting records show that 69% of eligible voters actually did vote. Given that 69% of eligible voters actually did vote, (a) find the probability that among 1466 randomly selected voters, at least 1049 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2 1049) = (Round to four decimal places as needed.) (b) What does the result from part (a)...
Please answer A), B) and C).A)Find the 95% confidence interval estimate of the proportion of people who say that they voted.B) Are the survey results consistent with the actual voter turnout of 61%? Why or why not?C) How would the confidence interval change if we increased the confidence level to 99%? Findthe 99% confidence interval estimate to support your answer.
M118 Worksheet Creating a Confidence interval, 2 Standard Deviation Approach (A) In a survey of 1002 people, 701 said that they had voted in a recent presidential election. Create a 9596 Cl for the percentage of all people who say they voted in the election () Voting records show that 61% of registered voters actually voted in the election, Is this data consistent with your CL. -250 +25D (2) A SRS of 1228 medical malpractice lawsults showed that 856 of...
31. Assume that women's heights are normally distributed with a mean given by μ=62.6 in, and a standard deviation given by σ=2.8 in. a. If 1 woman is randomly selected, find the probability that her height is between 62.2 in and 63.2 in.The probability is approximately (b) If 49 women are randomly selected, find the probability that they have a mean height less than 63 in .43. In a survey of 1345 people, 1029 people said they voted in a...
Given the sample data below, test the claim that the proportion of male voters who plan to vote Republican at the next presidential election is more than the percentage of female voters who plan to vote Republican. Use the P-value method of hypothesis testing and use a significance level of 0.10. Based on the result, can we say that Republicans resonate better with male voters than with female voters? Men: n1 = 250, x1 = 146 Women: n2 = 202,...