Question

1.) Voting records show that 61% of eligible voters actually did vote in a recent presidential...

1.) Voting records show that 61% of eligible voters actually did vote in a recent presidential election. In a survey of 1002 people, 70% said that they voted in that election.

  1. Use the survey results to test the claim that the percentage of all voters who say that they voted is equal to 61%.
  2. Test the claim by constructing an appropriate confidence interval.   
  3. What are the null and alternative hypotheses?
  4. What is the value of = significance level?
  5. Is the test two-tailed, left-tailed or right-tailed?
  6. What is the test statistic and what is its distribution?
  7. What is the value of the test statistic?
  8. What is the P-value?
  9. What is (are) the critical value(s)?
  10. How would you state a conclusion that addresses the original claim?
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Answer #1

- Here we have given that n = 1002 pe proportion of people in survey of 1002 that they voted in that election P= Proportion olower bound for pa 2012 Teatre 0.70 - (1.96x 0.70 xo 36 100 2 0.6716 1 bound upper for pt Z42 PCI-pl 070+ (1.96x 01080 30 100c) Here we have to test Но P=0.61 Vis HI: PE 0.61 d) Here we use level of significance - 20.05 tailed test el It is E) Underfor L=0.05 are i) The critical values and 1.96 -1.96 j) Now p-value ex (level of significance) O ooool Lo.05 calculated Izl iz table as follows:

Area 0.02 0.09 z 0.0 0.1 0.2 0,3 0.4 0.5 0.6 0.7 0.8 0.9 1,0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2.0 0 0.01 0.04 0.05 0.06 0.

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