Question

Suppose the events B and B2 are mutually exclusive and complementary events, such that P(B) = 0.12 and P(B2) = (1 – 0.12). Consider another event A such that P(AB) = 0.49 and P(A|B2) = 0.46 Complete parts (a) through (d) below. • Find P(Bin A). • Find P(B2n A) • Find P(A) using the results in parts (a) and (b). • Find P(B1A). (Round the result to 4 decimal places.) a. P(Bin A) b. P(B2N A) c. P(A) DID LAN

Answer 1

sd 1 Given PCB;) : 0.12 P(B):0.88 P(A/B) = o.ua P(A/B₂) : 0.46 B, and B2 mutually Exclusive and Events. complementary a) PCBnA) = P CAIB.) PCB,) 0.49 * 0.12 0.0588 by P(Ba nA) = P(A/B) - P(B2) 0.46 * 0.88 0. You 8 = c) P(A) : 0.0588 + 0.4048 0.4636 d) P(BIA) P(BNA) PCA) O, 0588 0.1268 0.4636

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