Question

Fe(NO) Na,SO, 3 (ag)4 (aq) ionic: net-ionic: Fe(NOys ()NaOH n- (aq) onic: net-ionic: Fe(NO g)+Na,S)- (aq) onic: net-ionic: QUESTIONS

Answer 1

Solution :-

At first we need to write the balanced molecular equation.

Then in the next step we write the ionic equation by splitting the ionic species into the respective ions

Then in the last step we cancel the spectator ions to get the net ionic equation

#1) Balanced reaction equation

2Fe(NO3)3(aq) + 3Na2SO4(aq) --- > Fe2(SO4)3(aq) + 6NaNO3(aq)

Ionic equation

2Fe^3+(aq) + 6NO3^-(aq) + 6Na^+(aq) + 3SO4^2-(aq) --- > 2Fe^3+(aq) + 3SO4^2-(aq) + 6Na^+(aq) +6NO3^-(aq)

Net ionic equation

Since all the reactants and products are soluble therefore it do not have net ionic equation.

#2) Balanced molecular equation

Fe(NO3)3(aq) + 3 NaOH(aq) ---- > Fe(OH)3(s) + 3NaNO3(aq)

Ionic equation

Fe^3+(aq) + 3NO3^-(aq) + 3 Na^+(aq) + 3OH^-(aq) ---- > Fe(OH)3(s) + 3Na^+(aq) + 3NO3^-(aq)

Net ionic equation

Fe^3+(aq) + 3OH^-(aq) ---- > Fe(OH)3(s)

#3)Balanced molecular equation

2Fe(NO3)3(aq) + 3Na2S(aq) ---- > Fe2S3(s) + 6NaNO3(aq)

Ionic equation

2Fe^3+(aq) + 6NO3^-(aq) + 6Na^+(aq) +3S^2-(aq) ---- > Fe2S3(s) + 6Na^+(aq) + 6NO3^-(aq)

Net ionic equation

2Fe^3+(aq) + 3S^2-(aq) ---- > Fe2S3(s)