Question

R1 R5 1000 6800 SR6 31.8kQ 15 SR2 R3 34.750 (R4 IRL 2.2ko 5.6ko 31kQ R8 W 2.7ko R7 34.7k R9 w 5.6ko Figure 1 Remove R2 and measure the current through RS and record the data. Replace R2 and remove R3, measure the current through RS again. Compare those results and Explain about the change if any. Use Thevenin theorem, Find the Vi and Ruh. Using the Vin and Recreate a new circuit and measure the current through RL and voltage across RL. Compare these results with results from step 2.

Answer 1

Solutions Rs.600 180.0 S.CO2 em SRC In ROM selon 0 Remove Ro & measure current through po rexistor. Ro-8.60 kn 0110 Ro $175 -5. 50 370 R - Ike ISV u7 56100 Ro and Ro Parallel to each other, let fauollable Equivalent Rosestone /o) - ROYRg 2.745.6. 7:22 R$+R9 2.415.6 Rot Ry are also in parallel to A Equivalent resistonce 1. Ry56 Ret Ry = 2.55 kn 0.15.6 Rot Rot in sonts and Parallel with Reso equivalent resistance(s) - Rot Rot) RL (1.844.7) 0) O Rot Rytre 1.844.741 Pirolka v R5 -0,6olon. SS.O.Polen 9.55 isu P = 1.82 km

from kel lest node voltage all as shown in fig 1. 1+12 P - Retste 15-u 2-55 0.68+0.86+1.82 150 voost 3.36 150 / 10+ 0.392 +0.2976) a = 14 volt 150 10.6096 12 - current through the Ro resistance 19 3.35 Rst SAP 0.60 t 0.86 +1.02 4.166MA 14 dy Replace Ro and remove Re. measure current through R. Agar After this modification, Ro will be porollel with Ru Pavivalowd resistanu (0) RRY HR 2.2% 5.6 2.21 :57 Mew circuit Rollen Rs-0-68 kn TO 3 .0.0601 1.57

25-v 150-1/10t kast 3.35) © I-579 150 - UX 10.93 V 150 Togg - 18-12 10.93 13.72 current through the Rs resistenu (h) - 3.368 73.72 -- 4.60 mA 16 Find Utha Rth RS Rioler 0.60108 NE leke RS3 SRy 2.2803 sutk s.6ke Ro-2-760 for Rth 5.6in short the uoltage source Rs-0.68kr RRP Ry 365 olka 2.20 4.8 R9 RoxRg 2.4* 5. 1.89 2.1+55 0.092K Neni 13.6 R R R 0.1 RS

Rooibom 0.072 ki -1.91 (Racy & Rs +P) x6.5 Reg+RetP+6.5 = (0.092 +0.88 +1-802) x 6.5 1.098 kr 0-09 +0.50 +1.02767 th- 1.85 per for With i n Rs.0.sofor P=1.821 - 1-102 kr Apply Ko + 12 0.60 11. 06 150-110 10.666 Gm 0.60 024611 uth L x 6i5kr - 1.5681066x103 Its a 1.56865 - 10.182 volte

Using thereinin uoltage & Resistance, New circuit diagrom Poth a ligola AA {RLEIK2 10.162 10.162 3.56 MA 1-ost for stop. 2 rowt . we know I coment is flowing through Pr, and 22 u also flowing throug through is rexistor. te resistor is combination of Ro Rz Y RL Rs 11.01 Rule from current divider Isto 1 Rot Pyth cured the Ri dhe 17107071 I = 4.056 mA