2) Hartree-Fock theory. The objective of this question is to look in more detail at the...
Questions 3-5 3. The predecessor to Hartree-Fock was the Hartree method, where the main difference is that the Hartree-Fock method includes an trial wavefunction by writing it as a Slater Determinant, while the Hartree method uses a simple product wavefunction that does not capture anti- symmetry. In particular, for a minimal-basis model of, the Hartree method's trial wavefunction is given in the while the Hartree-Fock trial wav is given by where and are molecular orbitals, and and coordinates of electron...
Koopman's theorem states that the ionization energy of a Hartree-Fock orbital is equal to its eigenvalue when acted on by the Fock operator. In this problem we will show Koopman's theorem by comparing the molecular energy before and after an electron is removed from the system, assuming the orbitals themselves remain unchanged. We will make use of the fact that the Hartree-Fock energy Exp(N) of a state with N electrons in spinorbitals {i} is given by Eur(N) = $(dilfulds) +...
2. The hydrogen atom [8 marks] The time-independent Schrödinger equation for the hydrogen atom in the spherical coordinate representation is where ao-top- 0.5298 10-10rn is the Bohr radius, and μ is the electon-proton reduced mass. Here, the square of the angular momentum operator L2 in the spherical coordinate representation is given by: 2 (2.2) sin θー sin θ 00 The form of the Schrödinger equation means that all energy eigenstates separate into radial and angular motion, and we can write...
All questions showing all work and units please Chemistry 101/103 Due date: Friday, November 14.2019 Problem Set 2: Atomic Structure and Chemical Bonding 1. (15 marks) When the excited electron in a hydrogen atom falls from an unknown level to n-5, a photon of 3740 nm wavelength is emitted. What is the initial position for this electron? 2. (15 marks) Answer and explain: a) How many electrons can have: i.n=3,1 = 2? ii.n=3,1-2, m/=0? iii. n=3,1=2, ms - +1/2? iv....