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1 & 6-10
6. When sodium metal is dropped into liquid water, the mixture releases gaseous hydrogen leaving behind a colorless solution
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Answer #1

1) reaction between sodium and water is given below

2Na(s) + 2H2O(l) ---->2 NaOH(aq) + H2(g)

6)
Co and Sn : among these two Co is more reactive than Sn [tin]
So Co will replace Sn from its salt solution
Being less reactive than Co, tin can not displace Co from the
salt solution of Cobalt.
So cobalt will corrode when placed in tin sulfate

the reaction is

Co(s) + SnSO4(aq) ----> CoSO4(aq) + Sn(s)
*******

7)
Cd(NO3)2(aq) + Na2S(aq) ---> CdS (s) + 2NaNO3 (aq)
precipitate formed is cadmium sulfide CdS
*****
8)
H2SO4(aq) + Ca(OH)2 (aq) ----> CaSO4(aq) + 2H2O (l)
*****
9)

2CH3OH (l) + 3 O2 (g)----> 2 CO2(g) + 4 H2O (l)
****
10)
molecular equation for the formation of BaSO4is given below
BaCL2 (aq) + Na2SO4 (aq) ---> BaSo4 (s) + 2 NaCl (aq)

Now spilt compounds in Aq.forms to ions we get

Total ionic equation :

Ba2+ (aq) + 2Cl- (aq) + 2Na+ (aq) +SO42-(aq) ---> BaSO4 (s) +2Cl- (aq) + 2Na+ (aq)


Now cancel spectator ions [2Cl- (aq) , 2Na+ (aq) ] to get

Net ionic equatoon :


Ba2+ (aq) +SO42-(aq) ---> BaSO4 (s)
**********************
Thank you >All solved .kindly up vote


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