Question

A tank is full of water. Find the work w required to pump the water out of the spout. (Use 9.8 m/s for 9. Use 1000 kg/m as the weight density of water. Assume that = 4 m, 4 m, c = 12 m, and d = m.) W- Enhanced Feedback Please try again. Try dividing the tank into thin horizontal slabs of height Ax. Let x be the distance between each slab and the sout. If the top surface of a slabhas area Ax), then the slabs volume is approximately Alxx. Use the volume to compute the force required to pump the water out, and multiply by x to compute the work required to pump the water out. The amount of work required to empty the tank can be written as a Riemann sum and converted into an integral Need Help?

Answer 1

cy d eg 7x y = ax y = 2a31by - Pg bc yzdy Let us consider a coloumn of (6/290) coleter with length c', width 2x' and height dy. Its volume dv=cx2xx dy Mans of the waiter coloumn is dm = pdv = 2p cady The work done in sising this coloum of water is dw - dmx gty 20 cх dy xg xy = 2Pg exy day =&ego (bytu) y dy [: y = 202/6 = x=by/za 3 Total Work done is war eg be f g² dy = eg be ( 23 jan eg bc . (a) 2.51810J = (loookalns) (9.8m/s(40 x12m) (4 mg taba). 1-34x10 pelinee Tirupati Kup:.0512) 2313360 - Thus the work done is rising the weeter to the height 'a' is 2.51x100 J = W,. The work done in sising the water from the height y= a to y= Atd is Wz PVgd [where Volume of the water (V) = { ab c] - Pgabcd 1000 ks 1m x 9.8m/sx 4m x Ymx12m x 3m 2.82x100 J = We Total work = W = Witwa = 15.33x1085 Чт 2 2