Question

(b) calculate the pH after the addition of 10.4 mL of base
(c) calculate the pH at halfway to the equivalence point
(d) calculate the pH at the equivalence point
(e) calculate the pH after the addition of 82.8 mL of base
Consider the titration of 41.4 mL of 0.240 MHF Kg = 3.5 x 10-4) with 0.185 M NaOH Calculate the pH at each of the following p
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Answer #1

HF t NGOH alaft ho 0.24M 0.185M 42.4 mi 0 10.4m! 9.936 mmol 1.924 mm of 8.0/2 mmol 1.924 mmol 1:924 sl.8 8.012 S1.8 M -4 It iс © at half way Calaf [HA] pH = pkq P께 - 3.45 @ At equivalent pone motes g Ngon = mores q nf 0.1850 v= 0.24 X 41.4 V: 53.7 ml} (о| е ИЕ f Чson Maf tho О. 2ЧИ 0.185M 41.4 m] 84.8 m/ 7. 936 mm 1 1S, 31 8 5.382 mmol ри Lл // De olo (4 ои Г. 38. Lon) - (

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