Can you explain the red arrow where they got 8 cos theta and 6
theta from...
r = 7 + 7 sine Now to u ** for nowcon bordo co – Nowy (or sin oy do = Sesingo) + 1° ao – S (suM9 + 2sin() + 1) ao = | sin?(O) do + 2 / sin(e) ao + /10 solo H Beach - formato The required Area is a- oo [_erinošao - - sin(20) + 8 cos(@) - 60 Hence, From (1) The required Area is A = 49 Í (1+sin )d0 = 49