Homework Answers
The statistic software output for this problem is:
t = 0.985
P-value = 0.1728
At 5% level of significance
P-value > 0.05
Fail to reject the null hypothesis .
There is not good evidence to conclude that the mean sugar content higher than 0.3
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Different cereals are randomly selected and the sugar content (grams of sugar per gram of cereal)...
4. Different cereals are randomly selected and the sugar content (grams of sugar per gram of...
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QUESTION 5 The pumber of grams of fat per serving for three different kinds of burger from several marylfacturers is listed below. Beef Burger Chicken Burger Fish Burger 23 25 26 24 26 26 41 26 43 24 24 36 27 25 39 28 25 23 32 i) At the 0.05 level of significance, is there sufficient evidence to conclude a difference in the mean of fat content? (16 marks) i) Construct the ANOVA Summary Table from the derived statistics....
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Ten randomly selected teenagers were each asked to list how many hours they watched TV per...
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A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.28 years and the standard deviation is 9.35 31 21 44 32 34 11 48 42 23 45 39 35 31 28 29 43 34 37 20 44 33 27 24 a) Construct a 80% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of...
years. A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.84 years and the standard deviation is 8.84 25 39 43 25 42p a) Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 23 28 42 45 31 interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed...
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