Question

Write a chemical equation to show (a) the main reaction in this experiment, (b) why Vanillin is more soluble in aq. NaOH than plain water, (c) why adding aq. HCI precipitates the product. (d) What would happen if we tried to carry out the reduction in aq. HCl instead of aq. NaOH? 1. 2. How many moles of hydride can be transferred from each mole of NaBHa? 3. Of the reagents used today, which one is both corrosive and flammable? 4. Of the solvents shown, circle the one that might be suitable for carrying out todays reaction. For each of the others, state in 5 words or less why it is an unsuitable solvent. 0.1M HC 5. (a) draw the product each compound below would form if treated with NaBH4 [ write N.R. for no reaction] OH OCH 3 CO 2H (b) What is the solvent used in the reduction of vanillin?* (c) Which of the above compounds is soluble enough in this solvent to undergo reduction like vanillin?* What is the significant difference in the IR spectrum between the starting material and product? 6. 76
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a) O M o c 4 HO vanilkn vani liyl alahol 쏘92. thR6xHgm-bhan bond and and aks neuhol

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