Question

write in c++

Another common technique to avoid having to pass a separate argument for the array's size is to make the first element of the array hold its size. Of course this only works for numeric arrays, but arrays of numbers are the most common kind.

Write the "copy_stock_prices" like before, but the first element contains the number of prices in the array, only copy those.

Answer 1

Answer:-

CODE:-

#include <iostream>

using namespace std;

int main()
{
cout<<"Hello World";
int stock_prices[7]={1,2,3,4,5,56,6}; //initalising actual array.
int copy_stock_prices[8]; //declaring variable in which actual array will bw copied.
copy_stock_prices[0]=7; //initalising first element of copy_stock_prices to size of array stock_prices
  
for(int i=1;i<8;i++)
{copy_stock_prices[i]=stock_prices[i-1]; //copying stock_price to copy_stock_prices
}
for(int i=0;i<8;i++)
{cout<<copy_stock_prices[i]<<" ";
  
}
return 0;
}

OUTPUT SCREENSHOT:-

main.cpp 2 #include <iostream> 4 using namespace std; 6 int main() cout<<"Hello World"; int stock_prices[7]={1,2,3,4,5,56,6}; int copy_stock_prices[8]; copy stock prices[@]=7; //initalising actual array. //declaring variable in which actual a //initalising first element of copy_stog for(int i=1;i<8;i++) {copy_stock_prices[i]=stock_prices[i-1]; //copying stock_price to copy_stock_pri for(int i=0;i<8;i++) {cout<<copy_stock_prices[i]<<" "; return 0; input Hello World7 1 2 3 4 5 56 6 ... Program finished with exit code o Press ENTER to exit console.

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