(a) If the molar solubility of
Cd3(AsO4)2 at 25 oC is
1.15e-07 mol/L, what is the Ksp at this
temperature?
Ksp = ??????
(b) It is found that 1.66e-06 g of
Ca3(PO4)2 dissolves per 100 mL of
aqueous solution at 25 oC. Calculate the
solubility-product constant for
Ca3(PO4)2.
Ksp = ?????
(c) The Ksp of PbF2 at 25 oC is
3.30e-08. What is the molar solubility of PbF2?
solubility =???????? mol/L
a) Given that molar solubility of Cd3(AsO4)2 , s = 1.15e-07 mol/L = 1.17 x 10-7 mol/L
Cd3(AsO4)2 -------------> 3Cd+2 + 2 AsO4-3
3s 2s
Ksp = (3s)3 (2s)2
= 108 x s5
= 108 x (1.17 x 10-7)5
= 236.78 x 10-35
Therefore, Ksp = 236.78 x 10-35
b) Given that 1.66e-06 g of Ca3(PO4)2 dissolves per 100 mL of aqueous solution at 25 oC.
Molarity of Ca3(PO4)2 = [mass of Ca3(PO4)2 / molar mass of Ca3(PO4)2] x [ 1/volume in Litres]
= [1.66 x 10-6 g/ 310 g/mol] x [1/ 0.1 L]
= 0.053 x 10-6 mol/L
Molar solubility (or) Molarity of Ca3(PO4)2 , s = 0.053 x 10-6 mol/L
Ca3(PO4)2 ---------------> 3Ca+2 + 2 PO4-3
3s 2s
Ksp = (3s)3 (2s)2
= 108 x s5
= 108 x (0.053 x 10-6 )5
= 4.5 x 10-35
Therefore, Ksp = 4.5 x 10-35
c) Given that Ksp of PbF2 at 25 oC is 3.30e-08.
Ksp = 3.30x 10-8
PbF2 --------------> Pb+2 + 2F-
s 2s s = molar solubility
Ksp= s (2s)2
Ksp = 4s3
3.30x 10-8 = 4s3
s= (3.30x 10-8/4)1/3
s = 0.00215
Therefore, molar solubility of PbF2 = 0.00215 mol/L
(a) If the molar solubility of Cd3(AsO4)2 at 25 oC is 1.15e-07 mol/L, what is the...
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