Question

a bowling ball of mass 1.7 kg is launched from a spring compressed by the distance d= 0.49 m at an angle of 45 degrees measured from the horizontal. It is observed that the ball reaches a maximum height of h= 4.8m, measured from the initial position of the ball. Let the gravitational potential energy be zero at the initial height of the bowling ball.

Part A.) What is the spring constant k, in newtons per meter?

Part B.) Calculate the speed of the ball, Vo in m/s, just after the launched.

Answer 1

B) Maximum height reached by the ball is u" sin' θ 2g 2g h 29.8 m/s2 )(4.8m L1 ins13717 m/s sin (45) A) According to the conservation of energy mv2 (1,7 kg)(13.7 17 m/s) k=7=- (049 m) 0.49 m)2一一= 6528 Nrn Cd