Question

Question 3 2 pts Please do not use a calculator for this problem. रिकार 2 2 3 4 5 (5.-1) Graph of f' Let f be a function defined on the closed interval -5 58s 5 with f(1) = 3. The graph of the derivative off, consists of two semicircles and two line segments, as shown above. (a) For -5 <x< 5, find all values x at which f has a relative maximum. Justify your answer. (b) For -5 < x < 5, find all values x at which the graph off has a point of inflection. Justify your answer. Upload Choose a File

Answer 1

." (5,-1) this is graph of fla) : fW=3 these at a=-3 and and a=4 : a f'(-3) = 0 & $(4)=0 and sign of fox) changes from . positive ito negative ... so at point relative maxima. sig oj súsaka-3 * Sign of f'al at d=4 .tf are relative maximum @ a=-3 and a=4 points.

had the seco. of the 1 6 point of inflection vi wwhere $"W)=o. id that means og f(a) , parallel Jo where tangent a axis . in the graph is parallel to: then f")=o ling Irso at a=-4 and at x = 1 I tangent in parallel to x axts J and at x=2 fa) day not a wrist because there is sharp turn so a=2 is not point of inflection so anno a=-4 a -4 and and x=-1 us point of inflection,

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