A group of students measured the interaction force between a wire in a magnetic field and...
A group of students measured the interaction force between a wire in a magnetic field and the magnet responsible for the field using a wire of length 4.1 cm. They obtained the following results. Current (mA) Force (N) -440 -0.0237 -110 -0.0119 380 0.0158 890 0.0277 1. Find the slope (with units). 2. Now, use the length of the wire to determine the strength of the magnetic field B in which the experiment was carried out.
Hi all, I just need help finding B for this Data Set! Any help is appreciated. A group of students performed the same "Force on a Wire" experiment that you did in class. They obtained the following results. Current (mA) Length (cm) Force (N) 899 4.0 0.0316 867 3.1 0.0237 888 2.1 0.0158 877 0.9 0.0079 (a) Analyze the data. (You will not submit this spreadsheet. However, the results will be needed later in this problem.) (i) Enter the above...
a) The force on a wire is a maximum of 8.50×10−2 N when placed between the pole faces of a magnet. The current flows horizontally to the right and the magnetic field is vertical. The wire is observed to "jump" toward the observer when the current is turned on. If the pole faces have a diameter of 19.0 cm , estimate the current in the wire if the field is 0.460 T . If the wire is tipped so that...
No referring, thanks.The force on a wire is a maximum of 4.50×10−2 N when placed between the pole faces of a magnet. The current flows horizontally to the right and the magnetic field is vertical. The wire is observed to "jump" toward the observer when the current is turned on.A) What type of magnetic pole is the top pole face? 1. South pole 2. North poleB) If the pole faces have a diameter of 14.0 cm , estimate the current...
A current-carrying wire of length 52.0 cm is positioned perpendicular to a uniform magnetic field. If the current is 15.0 A and it is determined that there is a magnetic force of 2.3 N on the wire due to the interaction of the current and field, what is the magnitude of the magnetic field? A. 0.52 T OB. 0.46 T: C.0.38 T, OD.0.29 T: E.0.18 T: OF. 0.12 T.
The force on a wire is a maximum of 4.50×10−2 N when placed between the pole faces of a magnet. The current flows horizontally to the right and the magnetic field is vertical. The wire is observed to "jump" toward the observer when the current is turned on.A) If the pole faces have a diameter of 14.0 cm , estimate the current in the wire if the field is 0.460 T .B) If the wire is tipped so that it...
The force on a wire is a maximum of 4.50×10−2 N when placed between the pole faces of a magnet. The current flows horizontally to the right and the magnetic field is vertical. The wire is observed to "jump" toward the observer when the current is turned on. Part B If the pole faces have a diameter of 19.0 cm , estimate the current in the wire if the field is 0.140 T . Express your answer to three significant...
PHYSICS LAB MAGNETISM II: FORCE ON A CURRENT-CARRYING WIRE-8 You can find datas from here the Link provided: https://www.youtube.com/channel/UCKZ_Kb4C9j-B3RSNBMv2s_w Equipment: 1 current-carrying wire set-up 1 power supply 1 ammeter Investigation 2: Relationship between force and length of a current-carrying wire In this section we will explore the relationship between the force on a current-carrying wire and the length of the wire. Investigation 2.1 Predict the dependence of the force on the length of the wire. If you were to plot...
#12 uniform magnetic field of strength (2T). Find the magnitude of the force on the wire. Answer in units of N 008 (part 1 of 2) 10.0 points A 10 A current is directed along the post- tive s-axis and perpendicularly to a uniform magnetic field. The conductor experiences a magnetic force per unit length of 0.19 N/min the negative y direction Calculate the magnitude of the magnetic field in the region through which the current 012 10.0 points Consider...
7. (5 points) The force exerted by a constant uniform magnetic field on a current-carrying wire of length L produces a force per unit length of Fi on the wire. If a wire twice as long and carrying the same current is placed in the same fiel with the same orientation, the force per unit length would be (b) FL (a) 2F (c) FL/2