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Consider a fusion reaction in which a proton fuses with a neutron to form a deuterium nucleus How much energy is released in

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Answer #1

A)

Mass defect, dm = 1.007276u + 1.008665u - 2.01355u = 0.00239u

Energy, E = mc^2 = 0.00239 x 931.5 = 2.23 MeV

B)

Dose = 38 x 10^-3/0.85 = 0.045 rad

Energy, E =0.045 x 0.01 x 75/4 = 8.38 mJ

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