Question

Given two fair dice, find the following: 2. The probability of rolling a seven (7) or an eleven (11) b. The probability of rolling a two (2), a three (3), or a twelve (12) An unfair coin, with P(heads) = 5/, is flipped 5 times. What is the probability more tails than heads occur? (Provided the setup-no calculation-explain your answer.)

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Answer 1

solution a) P(70811) = P(7) + P131) - P17,11) = 4 + + - B6 = b) P (2,3 or 12) P/2) + P(3) + P(12) - P (2,3) -P(3,12) -P|2, 12) + P P (2,3,12) =+ + -36-+ p (tails) = 8 n=5 P (More tails) = P(x= 3) + P (X= 4) + P 1x=5) Uncato +(s) , = [0,6033 0.6033