Question

QUESTION1 Two charges of charge 01-7.0 uC and 02-7.0 mC are separated by a distance d-20 cm. A student places a point charge q -1.0 at the midpoint between charges Q1 and Q2 horizontally and a vertical distance h 5.0 cm above the line from Q1 and Q2 at point A as shown Figure 1. Find the magnitude of the electric force on q in N (20 points).

Answer 1

2.

when Capacitors are connected in Series,

1/Ceq = 1/C1 + 1/C2

Which gives

Ceq = C1*C2/(C1 + C2)

C1 = 15 $\mu$ F & C2 = 30 $\mu$ F

Ceq = 15*30/(15 + 30)

Ceq = 10 $\mu$ F (Part A)

Now using equation

Qeq = Ceq*V

Qeq = 10*10^-6*18 = 180*10^-6 C

Qeq = 180 $\mu$ C

Since Capacitors are connected in Series, So charge on each capacitors will be same

Charge on 15 uF capacitor = 180 $\mu$ C (Part B)

Charge on 30 uF capacitor = 180 $\mu$ C (Part C)

Voltage on C1 will be

V1 = Q1/C1 = 180 $\mu$ C/15 $\mu$ F = 12 V (Part D)

Voltage on C2 will be

V2 = Q2/C2 = 180 $\mu$ C/30 $\mu$ F = 6 V (Part E)

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