Question

Specifications: • Prompt the user to input a wall's height and width. Calculate and output the wall's area. • Extend to also calculate and output the amount of paint in gallons needed to paint the wall. Assume a gallon of paint covers 350 square feet Store this value using a const double variable. • Extend to also calculate and output the number of 1 gallon cans needed to paint the wall. Hint: Use a math function to round up to the nearest gallon. Example Output: Enter wall height (feet): 12.0 Enter wall width (feet): 15.0 Wall area: 180 square feet Paint needed: 0.514286 gallons Cans needed: 1 can(s) Deliverables: • All source files (remember source files are.cpp and hpp and.h files) • All data files (if used by your program). • Screenshot of the software running on your machine. Submissions that do not include source files will receive an automatic grade of ZERO.

Answer 1

hello,

let us understand a little bit about number of cans of 1 gallon required to paint.

if paint needed = 0.514286 gallons, then you have to buy at least 1 gallon can to paint the wall.

if paint needed 0.4123 gallons, then also you have to buy at least 1 gallon paint to paint the wall.

So we have to round up the gallons needed to the next possible integer number.

as, for 0.514286, the round up value will be 1 and also , for 0.4123 , the round up value will be 1.

So using round function of "math.h" ,

the round(0.514286)=1, and since 1 gallon>0.514 gallon, so our need can be satisfied, but

the round(0.4123)=0, and 0 gallon<0.4123 gallon, so our need can not be satisfied using round function, so in situations like this where rounded value is less than amount of paint required, we will add 1 can extra,

So round(0.4123)=0 but 0<0.4123 so we will increment number of cans , and number of cans will be 1 , which will satisfy our need.

providing you the code for this problem:-

code starts here:-

#include <iostream>
#include<math.h>
using namespace std;

int main()
{
    double wall_height,wall_width,wall_area;
    double paint_required,cans_required;
    cout<<"Enter wall height (feet):";
    cin>>wall_height;
    cout<<"Enter wall width (feet):";
    cin>>wall_width;
    wall_area=wall_width*wall_height;
    cout<<"Wall area:"<<wall_area<<" square feet"<<endl;
    paint_required=wall_area/350;
    cout<<"Paint needed:"<<paint_required<<" gallons"<<endl;
    cans_required=round(wall_area/350);

    if(cans_required<paint_required)               //the condition to increment number of 1 gallon cans
        cans_required++;

    cout<<"Cans needed:"<<cans_required<<" can(s)";
}

code ends here:-

snapshot of the code:-

#include <iostream> #include<math.h> using namespace std; int main() double wall_height,wall_width,wall_area; double paint_required, cans required; cout<<"Enter wall height (feet):"; cin>>wall_height; cout<<"Enter wall width (feet):"; cin>>wall_width; wall_area=wall_width*wall_height; cout<<"Wall area:"<<wall_area<<" square feet"<<endl; paint_required=wall_area/350; cout<<"Paint needed:"<<paint_required<<" gallons"<<endl; cans_required=round(wall_area/350); if(cans_required paint_required) cans required++; cout<<"Cans needed:"<<cans_required<<" can(s)";

output snapshot:-

Enter wall height (feet):12.0 Enter wall width (feet):15.0 Wall area:180 square feet Paint needed:0.514286 gallons Cans needed:1 can (5) ... Program finished with exit code 0 Press ENTER to exit console. I

i hope i was able to solve your problem to a greater extent, please feel free to comment your queries, Please consider my efforts and upvote my solution.

Thanku:)