Question

An isotropic linear elastic ceramic like Brick has an Elastic Modulus of E = 242 GPa, and a Poisson's Ratio of nu = 0.25. A brick is made with dimensions: length L = 13 cm, diameter width = 5 cm and height h = 6 cm. This brick is laid at the bottom of a wall, resulting in a compressive stress in the height direction of 1,999 KN. As a result of this force, how much longer in the width direction will the brick become? (Assume linear elastic behavior, answer in cm to 4 decimal places.)

Answer 1

$0!?:- E = 242 GPg Let x- dię" in length y dign in width z-digh in hight = L = 13cm-130mm & W- 5cm = 50 mm = 6 cm = 60 mm V-0.25 load in z dich - P = - 1999 KN Ozz f. -1999x103. - 307,53 MP4 130x50 x = R20 Strain in y dien A lystė Log-> (6742]]= - -025 XC-307.53) 242x103 -IN + Wf. W= 31470 2104 4 31770 W * We = 50.04588 mm Soo this is final width 89 Bujck become .01588 mm longer. in width

Brick becomes 5.00158cm long

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