Question

VO I Home | My Classes - Help Log Out Calendar ment Gradebook Due Mon 02/10/20 The decomposition of N2O5, N,Os(8) + 2NO2(g) + 02() has a rate constant equal to k = 6.65 . 10-6 gill How much time in min does it take for the pressure to drop to 0.775 of its initial value? min Points possible: 10 Unlimited attempts. Submit

Answer 1

let initial value = 1

and

after time t min, value = 0.775

First order rate law is

ln ([A]0 / [A]) = K * t

or

ln (1 / 0.775) = 6.55 * 10^-5 * t

or

t = 3891.5 s = 3891.5 / 60 = 64.9 min [1 min = 60 s]

or

t = 64.9 min (answer)