Given the function y= -4cos1/2(x-π)+3, find the 2 maximum and minimum y-values of the function.

Question

Question

max = _______

min = _______

Answer 1

Answer #1

The extreme values of the function occur when cos(x - pie)/2 reaches its maximum and minimum values.

If cos(x - pie)/2 becomes 1 then y = -4(1) + 3 = -1

and if cos(x - pie)/2 becomes -1 then y= - 4( - 1 ) + 3 = 7 .

so maximum value of y is 7 and its minimum value is -1.

Answer 2

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