Question

The probability density of a random variable X is given in the figure below. From this density, the probability that X is bet

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Answer #1

We have given,

X\sim U(a=0,b=2)

f(x)=\frac{1}{b-a}=\frac{1}{2}

P[0.62<X<1.88]

=\int_{0.62}^{1.88}\frac{1}{2}dx

=\frac{1.88-0.62}{2}

=0.63

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