Question

An RLC series circuit has a 1.00 k2 resistor, a 150 mH inductor, and a 25.0 pF capacitor. Find the power factor at f = 7.10 H

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Answer #1

a)

net impedance

Z^2 = R^2 + ( 2 pi fL - 1/ ( 2 pi f C)) ^2

Z = 1339 ohm

power factor

cos x = R/Z = 0.7468

======

b)

x = 41.682

c)

av power

P = Vrms^2 cos x / Z

P = 350^2 * 0.7468 / 1339 = 38.322 W

=====

d)

Pr = Vrms^2/R = 122.5 W

=====

Comment before rate in case any doubt, will reply for sure.. goodluck

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