Question

Use the Central Limit Theorem for Sums to find the sample mean and sample standard deviation Question Suppose weights, in pounds, of dogs in a city have an unknown distribution with mean 26 and standard deviation 3 pounds. A sample of size n = 67 is randomly taken from the population and the sum of the values is computed. Using the Central Limit Theorem for Sums, what is the mean for the sample sum distribution? Provide your answer below: pounds

Answer 1

solution : Let x be the weight of a randomly selected dog. give mean of x = u(x) = 26 pound standard deviation of x=0(x) = 3 pound. sample size = v= 67 If x has unknown or known dist eibution. with mean ucx) and standard deviation ocx) and sample size is n, then according to cente al limit theonem, mean of sums of x = nx u(x) standard deviation of sums of x = into our mean 72 so our mean of sample sum distribution ul&x) = nx M(x) = 67826 = 1742 pounds.