In certain ranges of a piano keyboard, more than one string is tuned to the...

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In certain ranges of a piano keyboard, more than one string is tuned to the...

In certain ranges of a piano keyboard, more than one string is tuned

to the same note to provide extra loudness. For example, the note at

256 Hz has two strings at this frequency. If one string slips from

its normal tension of 840 N to 790 N, what difference in frequency is

heard when the hammer strikes the two strings simultaneously?

please show steps, I am more interested in the path taken for this problem. Thank You

science physics

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Answer 1

Answer #1

f is proportional to sqrt(T)
So the beat frequency = 256-(256*sqrt(790/840)) = 7.735 Hz

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Answer 2

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In certain ranges of a piano keyboard, more than one string is tuned to the...

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